x^2-5x=196

Solution for x^2-5x=196 equation:

x^2-5x=196

We move all terms to the left:

x^2-5x-(196)=0

a = 1; b = -5; c = -196;
Δ = b2-4ac
Δ = -52-4·1·(-196)
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{809}}{2*1}=\frac{5-\sqrt{809}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{809}}{2*1}=\frac{5+\sqrt{809}}{2}
$